Wrap the default servlet but override the default webapp path

Question

I have a folder of static html,imgs,flash content that lives outside of the webapp folder. Right now I\'m using a symbolic link to map that folder into my webapp directory.

Answer 1

You can change to a different path within your webapp context. Here's an example which does differential serving depending on whether the client's User-Agent supports ES6:

protected void service(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
    RequestDispatcher rd = getServletContext().getNamedDispatcher("default");
    HttpServletRequest wrapped = new HttpServletRequestWrapper(req) {
        @Override
        public String getServletPath() {
            String prefix = supportsES6(req) ? "/es6" : "/es5";
            String newPath =  prefix + req.getServletPath();
            if (newPath.endsWith("/")) newPath += "index.html";
            return newPath;
        }
    };
    rd.forward(wrapped, resp);
}

However, "es5" and "es6", even though we use the initial slash, are subdirectories of the webapp's ordinary context. It's not possible to break outside of the context directory using this method.