theano - use tensordot compute dot product of two tensor

Question

I want to use tensordot to compute the dot product of a specific dim of two tensors. Like:

A is a tensor, whose shape is (3, 4, 5) B is a tensor, whose shape is (3,

Answer 1

Well, do you want this in numpy or in Theano? In the case, where, as you state, you would like to contract axis 3 of A against axis 2 of B, both are straightforward:

import numpy as np

a = np.arange(3 * 4 * 5).reshape(3, 4, 5).astype('float32')
b = np.arange(3 * 5).reshape(3, 5).astype('float32')

result = a.dot(b.T)

in Theano this writes as

import theano.tensor as T

A = T.ftensor3()
B = T.fmatrix()

out = A.dot(B.T)

out.eval({A: a, B: b})

however, the output then is of shape (3, 4, 3). Since you seem to want an output of shape (3, 4), the numpy alternative uses einsum, like so

einsum_out = np.einsum('ijk, ik -> ij', a, b)

However, einsum does not exist in Theano. So the specific case here can be emulated as follows

out = (a * b[:, np.newaxis]).sum(2)

which can also be written in Theano

out = (A * B.dimshuffle(0, 'x', 1)).sum(2)
out.eval({A: a, B: b})