Cartesian product of a pandas dataframe with itself

Question

Given a dataframe:

    id  value
0    1     a
1    2     b
2    3     c

I want to get a new dataframe that is basically the cartesian produ

Answer 1

I had this problem before , this is my solution ..

import itertools
import pandas as pd 
c = list(itertools.product(DF.id.tolist(), DF.id.tolist()))
Dic=dict(zip(DF.id, DF.value))
df = pd.DataFrame(c , columns=['id', 'id_2'])
df[['value','value_2']]=df.apply(lambda x:x.map(Dic))
df.loc[df.id!=df.id_2,:]


Out[125]: 
   id  id_2 value value_2
1   1     2     a       b
2   1     3     a       c
3   2     1     b       a
5   2     3     b       c
6   3     1     c       a
7   3     2     c       b