Why is this Java operator precedence being ignored here?

Question

The following code prints out \"3\", not \"4\" as you might expect.

public class Foo2 {
    public static void main(String[] args) {
        int a=1, b=2;            


        

Answer 1

This isn't a matter of precedence, it's a matter of the definition of the operator. By definition the postfix operator executes after the variable is used in the enclosing expression.