A for loop without any {}

Question

So I was reading about shuffling an array. And then I came across this script:

shuffle = function(o){ //v1.0
    for(var j, x, i = o.length; i; j = parseInt(         


        

Answer 1

Looks like I didn't read the loop correctly.

In this case, the evaluations are happening inside the conditions of the for loop.

So a for loop has three parts

for (initial variables; end cases; what to do every iteration)

You define some initial stuff and use o which was passed into the function, define an end case, and then compute something every iteration. At the end, o has a new value and it gets returned.