Efficiently removing specific characters (some punctuation) from Strings in Java?

Question

In Java, what is the most efficient way of removing given characters from a String? Currently, I have this code:

private static String processWord(String x)          


        

Answer 1

Use String#replaceAll(String regex, String replacement) as

tmp = tmp.replaceAll("[,.;!?(){}\\[\\]<>%]", "");

System.out.println(
   "f,i.l;t!e?r(e)d {s}t[r]ig%".replaceAll(
                   "[,.;!?(){}\\[\\]<>%]", "")); // prints "filtered string"