Outputting integers in assembly on Linux

Question

This needs to be done in pure assembly (ie. no libraries or calls to C).

I understand the essence of the problem: one needs to divide the integer by 10, convert the

Answer 1

You properly set ecx to 10 at the top of your routine, but overwrite ecx later:

mov eax, 4              ; sys_write
mov ebx, 1              ; to STDOUT
mov ecx, edx ;;; oops -- lost the 10
mov edx, 1
int 0x80

Try moving the loop up one line, so ecx is re-initialized to 10 each time through the loop.