Single-Element-Vector Initialization in a Function Call

Question

Consider the following example code:

Example:

void print(int n) {
    cout << \"element print\\n\";
}

void print(vector

        

Answer 1

No thats not what you do, you`re creating an initializer_list.

See: http://en.cppreference.com/w/cpp/utility/initializer_list

Call 1) Single Element is called

Call 2) initializer_list creates an single int element

Call 3) A Vector object is given

Call 4) A Vector object is given

The Overload resulotion prefers to use the int parameter method before the std::vector parameter method, because there are less type conversions. The int parameter is a direct match, for the vector parameter an additional conversion is needed.

For example:

void print(std::initializer_list list){
    cout << "initializer_list print\n";
}

would result for call 2, that the output is "initializer_list print"