a += a++ * a++ * a++ in Java. How does it get evaluated?

Question

I came across this problem in this website, and tried it in Eclipse but couldn\'t understand how exactly they are evaluated.

    int x = 3, y = 7, z = 4;

          


        

Answer 1

Because a postincrement modifies the variable after the value is taken and += evaluates its left hand side before evaluating its right hand side,

x += x++ * x++ * x++; 

becomes

tmp0 = x

tmp1 = x
++x
tmp2 = tmp1 * x
++x
tmp3 = tmp2 * x
++x

x = tmp0 + x