JS ES6 Promise Chaining

Question

I\'m trying to learn how to use promises, but am having trouble comprehending the chaining. I assume that with this code, both promises will run. Then when I call test.then(

Answer 1

You may also want to try -

    let test = new Promise(function(resolve, reject){
        resolve('done1');
    });

    let test2 = new Promise(function(resolve, reject){
        resolve('done2');
    });

    try {
        let logOne = test();
        let logTwo = test2();
        console.log(logOne);
        console.log(logTwo);
    } catch(error) {
        console.error(error);
    }

In this way, you can also properly handle any promise dependencies. For example if test one relied on test two's data your could -

try {
        let logOne = test();
        let logTwo = test2(logOne);
        console.log(logOne);
        console.log(logTwo);
    } catch(error) {
        console.error(error);
    }