Where should I implement flask custom commands (cli)

Question

Creating custom commands in flask needs access to the app, which is generally created in app.py like this:

Answer 1

I have this layout:

baseapp.py

from flask import Flask

app = Flask("CmdAttempt")

app.py

from .baseapp import app

def main():
    app.run(
        port=5522,
        load_dotenv=True,
        debug=True
    )

if __name__ == '__main__':
    main()

commands.py

import click

from .baseapp import app


@app.cli.command("create-super-user")
@click.argument("name")
def create_super_user(name):
    print("Now creating user", name)


if __name__ == '__main__':
    from .app import main
    main()

In the console where you run the commands first define the FLASK_APP to be commands.py, then run the commands that you define.

set FLASK_APP=commands.py
export FLASK_APP=commands.py
flask create-super-user me

You can either use a separate terminal for built-in commands or clear the FLASK_APP variable before issuing them. In Linux is even easier because you can do

FLASK_APP=commands.py flask create-super-user me