I already read about realpath(), but is there a function that I can pass a base directory and a filename that would give me the following result without resolvi
I use Hardex's solution:
#include
char * normalizePath(char* pwd, const char * src, char* res) {
size_t res_len;
size_t src_len = strlen(src);
const char * ptr = src;
const char * end = &src[src_len];
const char * next;
if (src_len == 0 || src[0] != '/') {
// relative path
size_t pwd_len;
pwd_len = strlen(pwd);
memcpy(res, pwd, pwd_len);
res_len = pwd_len;
} else {
res_len = 0;
}
for (ptr = src; ptr < end; ptr=next+1) {
size_t len;
next = (char*)memchr(ptr, '/', end-ptr);
if (next == NULL) {
next = end;
}
len = next-ptr;
switch(len) {
case 2:
if (ptr[0] == '.' && ptr[1] == '.') {
const char * slash = (char*)memrchr(res, '/', res_len);
if (slash != NULL) {
res_len = slash - res;
}
continue;
}
break;
case 1:
if (ptr[0] == '.') {
continue;
}
break;
case 0:
continue;
}
if (res_len != 1)
res[res_len++] = '/';
memcpy(&res[res_len], ptr, len);
res_len += len;
}
if (res_len == 0) {
res[res_len++] = '/';
}
res[res_len] = '\0';
return res;
}
Example:
#include
int main(){
char path[FILENAME_MAX+1];
printf("\n%s\n",normalizePath((char*)"/usr/share/local/apps",(char*)"./../../../",path));
return 0;
}
Output:
/usr
char* which must have the required memory/capacity to contain the normalized path.