Split up a list at each element satisfying a predicate (Scala)

Question

In a text file I have data in the form:

1)
text
text
2)
more text
3)
even more text
more even text
even more text
...

I read it as a list o

Answer 1

I have the honor, to add an answer next to the great @MartinOdersky!

From Scala 2.13 we can use the List.unfold:

List.unfold(input) {
  case Nil =>
    None
  case x :: as =>
    as.span(!_.matches("""\d+\)""")) match {
      case (prefix, Nil) =>
        Some(x :: prefix, List.empty)
      case (prefix, suffix) =>
        Some(x :: prefix, suffix)
    }
}

Code run at Scastie.