How to select last row and also how to access PySpark dataframe by index?

Question

From a PySpark SQL dataframe like

name age city
abc   20  A
def   30  B

How to get the last row.(Like by df.limit(1) I can get first row o

Answer 1

How to get the last row.

Long and ugly way which assumes that all columns are oderable:

from pyspark.sql.functions import (
    col, max as max_, struct, monotonically_increasing_id
)

last_row = (df
    .withColumn("_id", monotonically_increasing_id())
    .select(max(struct("_id", *df.columns))
    .alias("tmp")).select(col("tmp.*"))
    .drop("_id"))

If not all columns can be order you can try:

with_id = df.withColumn("_id", monotonically_increasing_id())
i = with_id.select(max_("_id")).first()[0]

with_id.where(col("_id") == i).drop("_id")

Note. There is last function in pyspark.sql.functions/ `o.a.s.sql.functions but considering description of the corresponding expressions it is not a good choice here.

how can I access the dataframe rows by index.like

You cannot. Spark DataFrame and accessible by index. You can add indices using zipWithIndex and filter later. Just keep in mind this O(N) operation.