How to build an Rc or Rc<[T]>?

Question

I\'d like to create an Rc because I want reduce the indirection from following the 2 pointers that accessing an Rc require

Answer 1

Creating an Rc<[T]> can be done via coercions and as-casts from fixed sized arrays, e.g. coercions can be done as follows:

use std::rc::Rc;

fn main() {
    let x: Rc<[i32; 4]> = Rc::new([1, 2, 3, 4]);

    let y: Rc<[i32]> = x;

    println!("{:?}", y);
}

However, this doesn't work for strings, since they have no raw fixed-sized equivalent to create the first value. It is possible to do unsafely, e.g. by creating a UTF-8 encoded Rc<[u8]> and transmuting that to Rc. Theoretically there could be a crate on crates.io for it, but I can't find one at the moment.

An alternative is owning_ref, which isn't quite std::rc::Rc itself, but should allow, for example, getting an RcRef<..., str> pointing into an Rc. (This approach will work best if one uses RcRef uniformly in place of Rc, except for construction.)

extern crate owning_ref;
use owning_ref::RcRef;
use std::rc::Rc;

fn main() {
    let some_string = "foo".to_owned();

    let val: RcRef = RcRef::new(Rc::new(some_string));

    let borrowed: RcRef = val.map(|s| &**s);

    let erased: RcRef = borrowed.erase_owner();
}

The erasing means that RcRef<..., str>s can come from multiple different sources, e.g. a RcRef can come from a string literal too.

NB. at the time of writing, the erasure with RcRef requires a nightly compiler, and depending on owning_ref with the nightly feature:

[dependencies]
owning_ref = { version = "0.1", features = ["nightly"] }