strncpy or strlcpy in my case

Question

what should I use when I want to copy src_str to dst_arr and why?

char dst_arr[10];
char *src_str = \"hello\";

P

Answer 1

you should not use strncpy and not strlcpy for this. Better you use

*dst_arr=0; strncat(dst_arr,src_arr,(sizeof dst_arr)-1);

or without an initialization

sprintf(dst_arr,"%.*s",(sizeof dst_arr)-1,src_arr);

dst_arr here must be an array NOT a pointer.