strncpy or strlcpy in my case

Question

what should I use when I want to copy src_str to dst_arr and why?

char dst_arr[10];
char *src_str = \"hello\";

P

Answer 1

First of all, your dst_ptr has no space allocated and you haven't set it to point at the others, so assigning anything to that would probably cause a segmentation fault.

Strncpy should work perfectly fine - just do:

strncpy(dst_arr, src_str, sizeof(dst_arr));

and you know you wont overflow dst_arr. If you use a bigger src_str you might have to put your own null-terminator at the end of dst_arr, but in this case your source is < your dest, so it will be padded with nulls anyway.

This works everywhere and its safe, so I wouldn't look at anything else unless its intellectual curiousity.

Also note that it would be good to use a non-magic number for the 10 so you know the size of that matches the size of the strncpy :)