Correct method of a “static” Random.Next in C#?

Question

Why do i need to create an instance of Random class, if i want to create a random number between 1 and 100 ....like

Random rand = new Random();
rand.Next(1,1         


        

Answer 1

You need something similar to this if you want the syntax you mention.

namespace MyRandom
{
    public class Random
    {
        private static m_rand = new Random();
        public static Next(int min, int max)
        {
            return m_rand.Next(min, max);
        }
    }
}

This should allow you to do Random.Next(1,100); without having to worry about seeding.