Why does Math.Floor(Double) return a value of type Double?

Question

I need to get the left hand side integer value from a decimal or double. For Ex: I need to get the value 4 from 4.6. I tried using Math.Floor function but it\'s returning a

Answer 1

If you just need the integer portion of a number, cast the number to an int. This will truncate the number at the decimal point.

double myDouble = 4.6;
int myInteger = (int)myDouble;