Simplest way to loop between two NSDates on iPhone?

Question

What\'s the simplest way to loop from one date to another?

What I want conceptually is something like this:

for (NSDate *date = [[startDate copy] aut         


        

Answer 1

Add fast enumeration to a DateRange class:

- (NSUInteger)countByEnumeratingWithState: (NSFastEnumerationState *)state
                                  objects: (id *)stackbuf
                                    count: (NSUInteger)len;
{
    NSInteger days = 0;
    id current = nil;
    id components = nil;
    if (state->state == 0)
    {
        current = [NSCalendar currentCalendar];
        state->mutationsPtr = &state->extra[0];
        components = [current components: NSDayCalendarUnit
                                fromDate: startDate
                                  toDate: endDate
                                 options: 0];
        days = [components day];
        state->extra[0] = days;
        state->extra[1] = (uintptr_t)current;
        state->extra[2] = (uintptr_t)components;
    } else {
        days = state->extra[0];
        current = (NSCalendar *)(state->extra[1]);
        components = (NSDateComponents *)(state->extra[2]);
    }
    NSUInteger count = 0;
    if (state->state <= days) {
        state->itemsPtr = stackbuf;
        while ( (state->state <= days) && (count < len) ) {
            [components setDay: state->state];
            stackbuf[count] = [current dateByAddingComponents: components
                                                       toDate: startDate
                                                      options: 0];
            state->state++;
            count++;
        }
    }
    return count;
}

This is ugly, but the ugliness is confined to my date range class. My client code is just:

for (id date in dateRange) {
    NSLog( @"%@ in [%@,%@]", date, startDate, endDate );
}

I think this is probably a good enough reason to create a DateRange class if you don't have one already.