Count number of NULL values in each column in SQL

Question

I am trying to write a script that will show the number of non-null values in each column as well as the total number of rows in the table.

I have found a couple wa

Answer 1

As Paolo said, but here is an example:

DECLARE @TableName VARCHAR(512) = 'invoiceTbl';
DECLARE @SQL VARCHAR(1024);
WITH SQLText AS (
    SELECT 
        ROW_NUMBER() OVER (ORDER BY c.Name) AS RowNum,
        'SELECT ''' + c.name + ''', SUM(CASE WHEN ' + c.Name + ' IS NULL THEN 1 ELSE 0 END) AS NullValues FROM ' + @TableName AS SQLRow
    FROM 
        sys.tables t 
        INNER JOIN sys.columns c ON c.object_id = t.object_id
    WHERE 
        t.name = @TableName),
Recur AS (
    SELECT
        RowNum,
        CONVERT(VARCHAR(MAX), SQLRow) AS SQLRow
    FROM
        SQLText
    WHERE
        RowNum = 1
    UNION ALL
    SELECT
        t.RowNum,
        CONVERT(VARCHAR(MAX), r.SQLRow + ' UNION ALL ' + t.SQLRow)
    FROM
        SQLText t
        INNER JOIN Recur r ON t.RowNum = r.RowNum + 1
    )
SELECT @SQL = SQLRow FROM Recur WHERE RowNum = (SELECT MAX(RowNum) FROM Recur);
EXEC(@SQL);