Excel SUMIFS equivalent in R

Question

I\'m very very new to R and am looking at ways of recreating an Excel VBA macro and Excel worksheet functions such as SUMIFS. SUMIFS sums a column if the row has entries ma

Answer 1

You could do this with a loop or with a Cartesian merge. I don't know of any built in functions to do exactly this.

library(dplyr)

x = structure(list(StartDate = structure(c(1389312000, 1389484800, 
1390089600, 1390608000, 1390953600, 1391558400, 1391731200, 1391904000, 
1392681600), tzone = "UTC", class = c("POSIXct", "POSIXt")), 
    EndDate = structure(c(1390521600, 1390694400, 1391299200, 
    1391817600, 1392163200, 1392768000, 1392940800, 1393113600, 
    1393891200), tzone = "UTC", class = c("POSIXct", "POSIXt"
    )), Sample = c(139L, 136L, 422L, 762L, 899L, 850L, 602L, 
    180L, 866L)), .Names = c("StartDate", "EndDate", "Sample"
), row.names = c(NA, -9L), class = "data.frame")

x2 = x
names(x2)=c('StartDate2','EndDate2','Sample2')
x3 = merge(x,x2,allow.cartesian =T)
x4 = summarise(group_by(x3,StartDate,EndDate),
    sumifs=sum(Sample2[EndDate2 >= StartDate & StartDate2 <= EndDate]))
x_sumifs = merge(x,x4,by=c('StartDate','EndDate'))

This is what the output looks like.

> x_sumifs
   StartDate    EndDate Sample sumifs
1 2014-01-10 2014-01-24    139    697
2 2014-01-12 2014-01-26    136   1459
3 2014-01-19 2014-02-02    422   2358
4 2014-01-25 2014-02-08    762   3671
5 2014-01-29 2014-02-12    899   3715
6 2014-02-05 2014-02-19    850   4159
7 2014-02-07 2014-02-21    602   4159
8 2014-02-09 2014-02-23    180   3397
9 2014-02-18 2014-03-04    866   2498