Python asyncio force timeout

Question

Using asyncio a coroutine can be executed with a timeout so it gets cancelled after the timeout:

@asyncio.coroutine
def coro():
    yield from asyncio.sleep(         


        

Answer 1

Thx @dano for your answer. If running a coroutine is not a hard requirement, here is a reworked, more compact version

import asyncio, time

timeout = 0.5
loop = asyncio.get_event_loop()
future = asyncio.wait_for(loop.run_in_executor(None, time.sleep, 2), timeout)
try:
    loop.run_until_complete(future)
    print('Thx for letting me sleep')
except asyncio.exceptions.TimeoutError:
    print('I need more sleep !')

For the curious, a little debugging in my Python 3.8.2 showed that passing None as an executor results in the creation of a _default_executor, as follows:

self._default_executor = concurrent.futures.ThreadPoolExecutor()