Understand backspace (\b) behaviour in C

Question

This program copy its input to its output, replacing TAB(\\t) by \\t backspace(\\b) by \\b. But here in my code I am una

Answer 1

The backspace is consumed by the shell interpreter, so your program will never see it, also your code is (slightly) broken, due to misplaced braces, not helped by the poor indentation.

Here is a corrected version:

#include
int main(void)
{
    int c=0;
    while((c=getchar())!=EOF){
        if(c=='\t')
            printf("\\t");
        else if(c=='\b')
            printf("\\b");
        else
            putchar(c);
    }
    putchar('\n');
    return 0;
}

which works as expected:

$ echo 'vinay\thunachyal\b' | ./escape
vinay\thunachyal\b