Average time for datetime list

Question

Looking for fastest solution of time averaging problem.

I\'ve got a list of datetime objects. Need to find average value of time (excluding year, month, day). Here i

Answer 1

You would at least use sum() with a generator expression to create the total number of seconds:

from datetime import datetime, date, time

def avg_time(datetimes):
    total = sum(dt.hour * 3600 + dt.minute * 60 + dt.second for dt in datetimes)
    avg = total / len(datetimes)
    minutes, seconds = divmod(int(avg), 60)
    hours, minutes = divmod(minutes, 60)
    return datetime.combine(date(1900, 1, 1), time(hours, minutes, seconds))

Demo:

>>> from datetime import datetime, date, time, timedelta
>>> def avg_time(datetimes):
...     total = sum(dt.hour * 3600 + dt.minute * 60 + dt.second for dt in datetimes)
...     avg = total / len(datetimes)
...     minutes, seconds = divmod(int(avg), 60)
...     hours, minutes = divmod(minutes, 60)
...     return datetime.combine(date(1900, 1, 1), time(hours, minutes, seconds))
... 
>>> avg_time([datetime.now(), datetime.now() - timedelta(hours=12)])
datetime.datetime(1900, 1, 1, 7, 13)