What happens when you assign a literal constant to an rvalue reference?

Question

This is admittedly a nit-picky question that is mainly driven by curiosity. Suppose we have the following:

int x = 5;
int&& xref = std::move(x);
std         


        

Answer 1

int&& xref = 5;

... creates a temporary, initialized with 5, whose lifetime is extended to the end of the block.

The assignment

xref = 10;

changes the value of the still living temporary.