Can't pickle static method - Multiprocessing - Python

Question

I\'m applying some parallelization to my code, in which I use classes. I knew that is not possible to pick a class method without any other approach different of what Python

Answer 1

You could define a plain function at the module level and a staticmethod as well. This preserves the calling syntax, introspection and inheritability features of a staticmethod, while avoiding the pickling problem:

def aux():
    return "VoG - Sucess" 

class VariabilityOfGradients(object):
    aux = staticmethod(aux)

---

For example,

import copy_reg
import types
from itertools import product
import multiprocessing as mp

def _pickle_method(method):
    """
    Author: Steven Bethard (author of argparse)
    http://bytes.com/topic/python/answers/552476-why-cant-you-pickle-instancemethods
    """
    func_name = method.im_func.__name__
    obj = method.im_self
    cls = method.im_class
    cls_name = ''
    if func_name.startswith('__') and not func_name.endswith('__'):
        cls_name = cls.__name__.lstrip('_')
    if cls_name:
        func_name = '_' + cls_name + func_name
    return _unpickle_method, (func_name, obj, cls)


def _unpickle_method(func_name, obj, cls):
    """
    Author: Steven Bethard
    http://bytes.com/topic/python/answers/552476-why-cant-you-pickle-instancemethods
    """
    for cls in cls.mro():
        try:
            func = cls.__dict__[func_name]
        except KeyError:
            pass
        else:
            break
    return func.__get__(obj, cls)

copy_reg.pickle(types.MethodType, _pickle_method, _unpickle_method)

class ImageData(object):

    def __init__(self, width=60, height=60):
        self.width = width
        self.height = height
        self.data = []
        for i in range(width):
            self.data.append([0] * height)

    def shepard_interpolation(self, seeds=20):
        print "ImD - Success"       

def aux():
    return "VoG - Sucess" 

class VariabilityOfGradients(object):
    aux = staticmethod(aux)

    @staticmethod
    def calculate_orientation_uncertainty():
        pool = mp.Pool()
        results = []
        for x, y in product(range(1, 5), range(1, 5)):
            # result = pool.apply_async(aux) # this works too
            result = pool.apply_async(VariabilityOfGradients.aux, callback=results.append)
        pool.close()
        pool.join()
        print(results)


if __name__ == '__main__':  
    results = []
    pool = mp.Pool()
    for _ in range(3):
        result = pool.apply_async(ImageData.shepard_interpolation, args=[ImageData()])
        results.append(result.get())
    pool.close()
    pool.join()

    VariabilityOfGradients.calculate_orientation_uncertainty()   

yields

ImD - Success
ImD - Success
ImD - Success
['VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess', 'VoG - Sucess']

---

By the way, result.get() blocks the calling process until the function called by pool.apply_async (e.g. ImageData.shepard_interpolation) is completed. So

for _ in range(3):
    result = pool.apply_async(ImageData.shepard_interpolation, args=[ImageData()])
    results.append(result.get())

is really calling ImageData.shepard_interpolation sequentially, defeating the purpose of the pool.

Instead you could use

for _ in range(3):
    pool.apply_async(ImageData.shepard_interpolation, args=[ImageData()],
                     callback=results.append)

The callback function (e.g. results.append) is called in a thread of the calling process when the function is completed. It is sent one argument -- the return value of the function. Thus nothing blocks the three pool.apply_async calls from being made quickly, and the work done by the three calls to ImageData.shepard_interpolation will be performed concurrently.

Alternatively, it might be simpler to just use pool.map here.

results = pool.map(ImageData.shepard_interpolation, [ImageData()]*3)