What exactly does comparing Integers with == do?

Question

EDIT: OK, OK, I misread. I\'m not comparing an int to an Integer. Duly noted.

My SCJP book says:

When == is used to compare a primitive to a

Answer 1

No, I would not think that code print true, and you answered yourself exactly why.

When == is used to compare a primitive to a wrapper, the wrapper will be unwrapped and the comparison will be primitive to primitive.

and you then went on to compare two Integer references- that is, it compared the memory address of i1 and i2. You wanted either

Integer i1 = 1;
Integer i2 = new Integer(1);
System.out.println(i1.equals(i2));

Or

int i1 = 1;
Integer i2 = new Integer(1);
System.out.println(i1 == i2);