Firebase - How do I write multiple orderByChild for extracting data?

Question

I\'m looking to get data where two fields equal what I\'m passing in.

Here\'s an example of my code:

this.refApp
  .orderByChild(\'u         


        

Answer 1

An other way to do kind of multiple orderByChild in Firebase is to create an orderKey.

Imagine you have this in your base:

{
    userId: {
        firstName: 'Snow',
        lastName: 'Jon',
        birthYear: 283
    }
}

And you want to query: userRef.orderByChild('firstName').equalTo('Jon').orderByChild('lastName').equalTo('Snow')

You need to create a key on your user like this:

{
    userId: {
        firstName: 'Snow',
        lastName: 'Jon',
        birthYear: 283,
        orderName: 'JonSnow'
    }
}

So you can query like this: userRef.orderByChild('orderName').equalTo('JonSnow')

This also works with startAt and endAt if you want to query all the Snow born in a range of years. You first create the key:

{
    userId: {
        firstName: 'Snow',
        lastName: 'Jon',
        birthYear: 283,
        orderNameYear: 'Snow283'
    }
}

So you can query: userRef.orderByChild('orderNameYear').startAt('Snow280').endAt('Snow285')

This will return all Snow born between 280 and 285.