typesafe typedef in C++

Question

I would like to use something like typedef in my C++ programs to enhance type safety.

As an example, suppose I have two functions

void function1(unsi         


        

Answer 1

As you say, a typedef won't help you here. I can't think of a better way immediately, however if you go with your wrapping in a struct/class option you could use a conversion operator to eliminate the member method or function call.

For example:

struct WrappedType
{
    operator type()
    {
         return _value;
    }

    type _value;  
}

I'm not saying this is the way to do it mind you ;-)