using index() on multidimensional lists

Question

For a one dimensional list, the index of an item is found as follows:

 a_list = [\'a\', \'b\', \'new\', \'mpilgrim\', \'new\']
 a_list.index(\'mpilgrim\')
         


        

Answer 1

You can use the following sample method too:

data = [[1, 1,2],[12,4],[6]]

def m_array_index(arr, searchItem):
    for i,x in enumerate(a):
        for j,y in enumerate(x):
            if y == searchItem:
                return i,j
    return -1,-1#not found

print m_array_index(data, 6)

Or with all occurrences(sure code could be optimized - modified to work with generators and so on - but here is just a sample):

occurrences = lambda arr, val: tuple((i,j) for i,x in enumerate(arr) for j,y in enumerate(x) if y == val) or ((-1,-1))

print occurrences(data, 1) # ((0, 0), (0, 1))
print occurrences(data, 12) # ((1, 0),)
print occurrences(data, 11) # (-1, -1)