Is Math.IEEERemainder(x,y) equivalent to x%y?

Question

Is there any differences between Math.IEEERemainder(x,y) and x%y ?

Answer 1

No, they're not the same; see the documentation.

Here's the source:

    public static double IEEERemainder(double x, double y) { 
        double regularMod = x % y;
        if (Double.IsNaN(regularMod)) { 
            return Double.NaN;
        }
        if (regularMod == 0) {
            if (Double.IsNegative(x)) { 
                return Double.NegativeZero;
            } 
        } 
        double alternativeResult;
        alternativeResult = regularMod - (Math.Abs(y) * Math.Sign(x)); 
        if (Math.Abs(alternativeResult) == Math.Abs(regularMod)) {
            double divisionResult = x/y;
            double roundedResult = Math.Round(divisionResult);
            if (Math.Abs(roundedResult) > Math.Abs(divisionResult)) { 
                return alternativeResult;
            } 
            else { 
                return regularMod;
            } 
        }
        if (Math.Abs(alternativeResult) < Math.Abs(regularMod)) {
            return alternativeResult;
        } 
        else {
            return regularMod; 
        } 
    }