Is Math.IEEERemainder(x,y) equivalent to x%y?

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谎友^
谎友^ 2020-12-10 03:05

Is there any differences between Math.IEEERemainder(x,y) and x%y ?

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  •  独厮守ぢ
    2020-12-10 03:44

    No, they are not equivalent. MSDN shows the different formulas used for modulo and for IEEERemainder and has a short sample program exhibiting the differences:

    IEEERemainder = dividend - (divisor * Math.Round(dividend / divisor))
    
    Modulus = (Math.Abs(dividend) - (Math.Abs(divisor) * 
          (Math.Floor(Math.Abs(dividend) / Math.Abs(divisor))))) * 
          Math.Sign(dividend)
    

    Some examples where they have different/identical output (taken from MSDN):

                             IEEERemainder              Modulus
       3 / 2 =                          -1                    1
       4 / 2 =                           0                    0
       10 / 3 =                          1                    1
       11 / 3 =                         -1                    2
       27 / 4 =                         -1                    3
       28 / 5 =                         -2                    3
       17.8 / 4 =                      1.8                  1.8
       17.8 / 4.1 =                    1.4                  1.4
       -16.3 / 4.1 =    0.0999999999999979                   -4
       17.8 / -4.1 =                   1.4                  1.4
       -17.8 / -4.1 =                 -1.4                 -1.4
    

    See also this good answer by sixlettervariables on a similar question.

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