ArraySegment - Returning the actual segment C#

Question

I have been looking around on ways to return the segment which is basically held by ArraySegment in terms of offset and count. Although ArraySegment holds the complete and o

Answer 1

I use the following set of extension methods to work with array segments:

    #region ArraySegment related methods

    public static ArraySegment GetSegment(this T[] array, int from, int count)
    {
        return new ArraySegment(array, from, count);
    }

    public static ArraySegment GetSegment(this T[] array, int from)
    {
        return GetSegment(array, from, array.Length - from);
    }

    public static ArraySegment GetSegment(this T[] array)
    {
        return new ArraySegment(array);
    }

    public static IEnumerable AsEnumerable(this ArraySegment arraySegment)
    {
        return arraySegment.Array.Skip(arraySegment.Offset).Take(arraySegment.Count);
    }

    public static T[] ToArray(this ArraySegment arraySegment)
    {
        T[] array = new T[arraySegment.Count];
        Array.Copy(arraySegment.Array, arraySegment.Offset, array, 0, arraySegment.Count);
        return array;
    }

    #endregion

You can use them as follows:

byte[] input = new byte[5]{1,2,3,4,5};
ArraySegment delimited = input.GetSegment(0, 2);
byte[] segment = delimited.ToArray();