SQL to find upper case words from a column

Question

I have a description column in my table and its values are:

This is a EXAMPLE
This is a TEST
This is a VALUE

I want to display only EXAMPLE

Answer 1

Here's another solution. It was inspired by Aleksej's answer.

The idea? Get all the words. Then aggregate only fully uppercased to a list.

Sample data:

 create table descriptions (ID int, Description varchar2(100));

 insert into descriptions (ID, Description) 
 select 1 as ID, 'foo Foo FOO bar Bar BAR' as Description from dual 
 union all select 2, 'This is an EXAMPLE TEST Description VALUE' from dual
 ;

Query:

 select id, Description, listagg(word, ',') within group (order by pos) as UpperCaseWords
 from (
     select 
      id, Description,
      trim(regexp_substr(Description, '\w+', 1, level)) as word,
      level as pos           
     from descriptions t
     connect by regexp_instr(Description, '\s+', 1, level - 1) > 0
       and prior id = id
       and prior sys_guid() is not null
     )
 where word = upper(word)
 group by id, Description

Result:

ID | DESCRIPTION                               | UPPERCASEWORDS    
-- | ----------------------------------------- | ------------------
 1 | foo Foo FOO bar Bar BAR                   | FOO,BAR           
 2 | This is an EXAMPLE TEST Description VALUE | EXAMPLE,TEST,VALUE