async await with setInterval

Question

function first(){
  console.log(\'first\')
}
function second(){
  console.log(\'second\')
}
let interval = async ()=>{
  await setInterval(first,2000)
  await set         


        

Answer 1

You have a few problems:

1. Promises may only ever resolve once, setInterval() is meant to call the callback multiple times, Promises do not support this case well.
2. Neither setInterval(), nor the more appropriate setTimeout() return Promises, therefore, awaiting on them is pointless in this context.

You're looking for a function that returns a Promise which resolves after some times (using setTimeout(), probably, not setInterval()).

Luckily, creating such a function is rather trivial:

async function delay(ms) {
  // return await for better async stack trace support in case of errors.
  return await new Promise(resolve => setTimeout(resolve, ms));
}

With this new delay function, you can implement your desired flow:

function first(){
  console.log('first')
}
function second(){
  console.log('second')
}
let run = async ()=>{
  await delay(2000);
  first();
  await delay(2000)
  second();
}
run();