What is the inverse of the numpy cumsum function?

Question

If I have z = cumsum( [ 0, 1, 2, 6, 9 ] ), which gives me z = [ 0, 1, 3, 9, 18 ], how can I get back to the original array [ 0, 1, 2, 6, 9 ]<

Answer 1

You can use np.diff to compute elements 1...N which will take the difference between any two elements. This is the opposite of cumsum. The only difference is that diff will not return the first element, but the first element is the same in the original and cumsum output so we just re-use that value.

orig = np.insert(np.diff(z), 0, z[0])

Rather than insert, you could also use np.concatenate

orig = np.concatenate((np.array(z[0]).reshape(1,), np.diff(z)))

We could also just copy and replace elements 1...N

orig = z.copy()
orig[1:] = np.diff(z)