Erasing vector::end from vector

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谎友^
谎友^ 2020-12-10 00:45

Does it works correct(does nothing) when I use

 vector v;
 v.erase(v.end());

I want to use something like

 v.erase         


        
3条回答
  •  失恋的感觉
    2020-12-10 01:35

    The standard doesn't quite spell it out, but v.erase(q) is defined, "Erases the element pointed to by q" in [sequence.reqmts]. This means that q must actually point to an element, which the end iterator doesn't. Passing in the end iterator is undefined behavior.

    Unfortunately, you need to write:

    auto it = std::find(...);
    if (it != ) {
        v.erase(it);
    }
    

    Of course, you could define:

    template typename
    Iterator my_erase(Sequence &s, Iterator it) {
        if (it == s.end()) return it;
        return s.erase(it);
    }
    
    my_erase(v, std::find(v.begin(), v.end(), whatever));
    

    c.erase() on an associative container returns void, so to generalize this template to all containers you need some -> decltype action.

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