How to sort 1 array in Swift / Xcode and reorder multiple other arrays by the same keys changes

Question

Sorry for the complex wording of the question. My main experience is with PHP and it has a command called array_multisort. The syntax is below:

bool array_mu         


        

Answer 1

You could create an array of indexes in sorted order and use it as a mapping:

var names = [ "Paul", "John", "David" ]
var ages  = [  35,    42,     27 ]

let newOrder = names.enumerate().sort({$0.1<$1.1}).map({$0.0})

names = newOrder.map({names[$0]})
ages  = newOrder.map({ages[$0]})

[EDIT] Here's an improvement on the technique :

It's the same approach but does the sorting and assignment in one step. (can be reassigned to original arrays or to separate ones)

(firstNames,ages,cities,countries,actives) = 
    {( 
       $0.map{firstNames[$0]}, 
       $0.map{ages[$0]}, 
       $0.map{cities[$0]},
       $0.map{countries[$0]}, 
       $0.map{actives[$0]} 
    )} 
    (firstNames.enumerated().sorted{$0.1<$1.1}.map{$0.0})

[EDIT2] and an Array extension to make it even easier to use if you are sorting in place:

extension Array where Element:Comparable
{
   func ordering(by order:(Element,Element)->Bool) -> [Int]
   { return self.enumerated().sorted{order($0.1,$1.1)}.map{$0.0} }
}

extension Array 
{
   func reorder(_ otherArray:inout [T]) -> [Element] 
   {
      otherArray = self.map{otherArray[$0 as! Int]}
      return self
   }
}


firstNames.ordering(by: <)
          .reorder(&firstNames)
          .reorder(&ages)
          .reorder(&cities)
          .reorder(&countries)
          .reorder(&actives)

combining the previous two:

extension Array
{
   func reordered(_ otherArray:[T]) -> [T] 
   {
      return self.map{otherArray[$0 as! Int]}
   }
}

(firstNames,ages,cities,countries,actives) = 
    {( 
       $0.reordered(firstNames), 
       $0.reordered(ages), 
       $0.reordered(cities),
       $0.reordered(countries), 
       $0.reordered(actives) 
    )} 
    (firstNames.ordering(by:<))