Array decay to pointers in templates

Question

Please consider this code:

#include 

template
void f(T x) {
    std::cout << sizeof(T) << \'\\n\';
}

int main         


        

Answer 1

Depending on your use case, you can work around that using references:

template
void f(const T& x) {
    std::cout << sizeof(T);
}

char a[27];
f(a);

That prints 27, as desired.