Obtain & manipulate bit pattern of float as integer

Question

In Python 2.5, I have a float and I\'d like to obtain and manipulate its bit pattern as an integer.

For example, suppose I have

x = 173.3125
<         


        

Answer 1

You can get the string you want (apparently implying a big-endian, 32-bit representation; Python internally uses the native endianity and 64-bits for floats) with the struct module:

>>> import struct
>>> x = 173.125
>>> s = struct.pack('>f', x)
>>> ''.join('%2.2x' % ord(c) for c in s)
'432d2000'

this doesn't yet let you perform bitwise operations, but you can then use struct again to map the string into an int:

>>> i = struct.unpack('>l', s)[0]
>>> print hex(i)
0x432d2000

and now you have an int which you can use in any sort of bitwise operations (follow the same two steps in reverse if after said operations you need to get a float again).