Java - Decimal Format.parse to return double value with specified number of decimal places

Question

I want to be able to convert a string to a Double given a number of decimal places in a format string. So \"###,##0.000\" should give me a Double

Answer 1

Sure you can. Try running this:

String in = "1,234567";
System.out.println(NumberFormat.getNumberFormat(new Locale("fr", "FR")).parse(in));
System.out.println(NumberFormat.getNumberFormat(new Locale("en", "GB")).parse(in));

Clearly they result in different output, the first reading 1.234567 and the second 1234567. Maybe there's something wrong with your pattern? Anyway the last line there would be the preferred way of getting the UK standard format.