g++ treats returned string literal as const char pointer not const char array

Question

I\'m seeing some odd behaviour when returning a string literal from a function that should perform an implicit conversion with g++ (version 4.7.3). Can anyone explain why t

Answer 1

If you want a reusable C++03 workaround (i.e. one in which you won't have to care about what the return type is, as long it is constructible from a char array), you will have to use some kind of a char array wrapper.

template 
struct char_array_ref
{
    typedef const char (&ref_type)[N];
    ref_type ref;

    template 
    operator T() const
    {
        return T(ref);
    }
};

template 
char_array_ref stupid_gxx_use_array_reference(const char (&chars)[N])
{
    return char_array_ref { chars };
}


Test fn()
{
  return stupid_gxx_use_array_reference("foo");
}

Should be easy to regex propagate this across your codebase, too.

Obviously, in your code you can change stupid_gxx_use_array_reference into something less verbose.