JavaScript type conversion: (true && 1) vs (true | | 1)

Question

JavaScript is non-strictly typed language as Java,for example.

As we know, it converts value of result dependently upon context:

\"2\" + \"3\" r

Answer 1

You can do other things too like:

var myVar = Math.random() > 0.5;

myVar && doFunc();

which is the same as

if(myVar) {
    doFunc();
}

The || basically means "If the first thing is false, go to second"

The && basically means "If the first thing is true, go to the second"

This is why you see things like this at the top of functions:

function myFunction(options) {
    options = options || {};
}

Which means: If options is falsey, make it {}