JavaScript type conversion: (true && 1) vs (true | | 1)

Question

JavaScript is non-strictly typed language as Java,for example.

As we know, it converts value of result dependently upon context:

\"2\" + \"3\" r

Answer 1

This has nothing to do with type conversion.

|| returns the first truthy operand. 1 || true will give you 1

&& returns the first falsy operand, or the second operand if both are truthy.

See page 58 of the ECMAScript specification