How to replace a value with the output of a command in a text file?

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伪装坚强ぢ
伪装坚强ぢ 2020-12-09 16:12

I have a file that contains:

I want to replace in bash, the value 0

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  •  猫巷女王i
    2020-12-09 16:43

    In general, do use this syntax:

    sed "s//$(command)/" file
    

    This will look for and replace it with the output of command.


    For your specific problem, you can use the following:

    sed "s/0/$(date +%s)/g" input.txt > output.txt
    

    This replaces any 0 present in the file with the output of the command date +%s. Note you need to use double quotes to make the command in $() be interpreted. Otherwise, you would get a literal $(date +%s).

    If you want the file to be updated automatically, add -i to the sed command: sed -i "s/.... This is called in-place editing.


    Test

    Given a file with this content:

    Let's see what it returns:

    $ sed "s/0/$(date +%s)/g" file
    

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