I\'m fairly new to SQL and I was trying to get a full list of products that match a user input of a productID. Something like:
SELECT ProductID, ProductName
You can convert int to string using CONVERT(ProductID, CHAR(16)) AS ProductID and then use LIKE. So in your case it would be
SELECT ProductID, ProductName FROM Products
WHERE CONVERT(ProductID, CHAR(16)) LIKE '%15%'
You should remember that the query will make a full table scan without any support from indices. As a result it will be really expensive and time consuming.