How to change color of drawable shapes in android

Question

I am developing small android application in which I set drawable resource as background for linear layout. Now what I want to do change background color of linear layout dy

Answer 1

You could try something like this :

Drawable sampleDrawable = context.getResources().getDrawable(R.drawable.balloons); 
sampleDrawable.setColorFilter(new PorterDuffColorFilter(0xffff00,PorterDuff.Mode.MULTIPLY));

and for more you could refer to :

How to change colors of a Drawable in Android?

Change drawable color programmatically

Android: Change Shape Color in runtime

http://pastebin.com/Hd2aU4XC

You could also try this :

private static final int[] FROM_COLOR = new int[]{49, 179, 110};
private static final int THRESHOLD = 3;

public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.test_colors);

    ImageView iv = (ImageView) findViewById(R.id.img);
    Drawable d = getResources().getDrawable(RES);
    iv.setImageDrawable(adjust(d));
}

private Drawable adjust(Drawable d)
{
    int to = Color.RED;

    //Need to copy to ensure that the bitmap is mutable.
    Bitmap src = ((BitmapDrawable) d).getBitmap();
    Bitmap bitmap = src.copy(Bitmap.Config.ARGB_8888, true);
    for(int x = 0;x < bitmap.getWidth();x++)
        for(int y = 0;y < bitmap.getHeight();y++)
            if(match(bitmap.getPixel(x, y))) 
                bitmap.setPixel(x, y, to);

    return new BitmapDrawable(bitmap);
}

private boolean match(int pixel)
{
    //There may be a better way to match, but I wanted to do a comparison ignoring
    //transparency, so I couldn't just do a direct integer compare.
    return Math.abs(Color.red(pixel) - FROM_COLOR[0]) < THRESHOLD && Math.abs(Color.green(pixel) - FROM_COLOR[1]) < THRESHOLD && Math.abs(Color.blue(pixel) - FROM_COLOR[2]) < THRESHOLD;
}

as given in How to change colors of a Drawable in Android?