checking wget's return value [if]

Question

I\'m writing a script to download a bunch of files, and I want it to inform when a particular file doesn\'t exist.

r=`wget -q www.someurl.com`
if [ $r -ne 0          


        

Answer 1

I been trying all the solutions without lucky.

wget executes in non-interactive way. This means that wget work in the background and you can't catch de return code with $?.

One solution it's to handle the "--server-response" property, searching http 200 status code Example:

wget --server-response -q -o wgetOut http://www.someurl.com
sleep 5
_wgetHttpCode=`cat wgetOut | gawk '/HTTP/{ print $2 }'`
if [ "$_wgetHttpCode" != "200" ]; then
    echo "[Error] `cat wgetOut`"
fi

Note: wget need some time to finish his work, for that reason I put "sleep 5". This is not the best way to do but worked ok for test the solution.