How to get RTSP URL?

后端 未结 3 771
无人及你
无人及你 2020-12-09 14:32

I am Developing an application which consists of video-view,Here is my problem

  1. when I have loaded normal url is not working,The URL of Youtube
  2. How
3条回答
  •  无人及你
    2020-12-09 14:45

    Note:Working only android mobile(Not in Tablet)

    private class YourAsyncTask extends AsyncTask
        {
            ProgressDialog progressDialog;
    
            @Override
            protected void onPreExecute()
            {
                super.onPreExecute();
                progressDialog = ProgressDialog.show(AlertDetail.this, "", "Loading Video wait...", true);
            }
    
            @Override
            protected Void doInBackground(Void... params)
            {
                try
                {
                    String url = "http://www.youtube.com/watch?v=1FJHYqE0RDg";
                    videoUrl = getUrlVideoRTSP(url);
                    Log.e("Video url for playing=========>>>>>", videoUrl);
                }
                catch (Exception e)
                {
                    Log.e("Login Soap Calling in Exception", e.toString());
                }
                return null;
            }
    
            @Override
            protected void onPostExecute(Void result)
            {
                super.onPostExecute(result);
                progressDialog.dismiss();
    /*
                videoView.setVideoURI(Uri.parse("rtsp://v4.cache1.c.youtube.com/CiILENy73wIaGQk4RDShYkdS1BMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp"));
                videoView.setMediaController(new MediaController(AlertDetail.this));
                videoView.requestFocus();
                videoView.start();*/            
                videoView.setVideoURI(Uri.parse(videoUrl));
                MediaController mc = new MediaController(AlertDetail.this);
                videoView.setMediaController(mc);
                videoView.requestFocus();
                videoView.start();          
                mc.show();
            }
    
        }
    
    public static String getUrlVideoRTSP(String urlYoutube)
        {
            try
            {
                String gdy = "http://gdata.youtube.com/feeds/api/videos/";
                DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
                String id = extractYoutubeId(urlYoutube);
                URL url = new URL(gdy + id);
                HttpURLConnection connection = (HttpURLConnection) url.openConnection();
                Document doc = documentBuilder.parse(connection.getInputStream());
                Element el = doc.getDocumentElement();
                NodeList list = el.getElementsByTagName("media:content");///media:content
                String cursor = urlYoutube;
                for(int i = 0; i < list.getLength(); i++)
                {
                    Node node = list.item(i);
                    if(node != null)
                    {
                        NamedNodeMap nodeMap = node.getAttributes();
                        HashMap maps = new HashMap();
                        for (int j = 0; j < nodeMap.getLength(); j++)
                        {
                            Attr att = (Attr) nodeMap.item(j);
                            maps.put(att.getName(), att.getValue());
                        }
                        if(maps.containsKey("yt:format"))
                        {
                            String f = maps.get("yt:format");
                            if (maps.containsKey("url"))
                            {
                                cursor = maps.get("url");
                            }
                            if (f.equals("1"))
                                return cursor;
                        }
                    }
                }
                return cursor;
            }
            catch(Exception ex)
            {
                Log.e("Get Url Video RTSP Exception======>>", ex.toString());
            }
            return urlYoutube;
    
        }
    
    protected static String extractYoutubeId(String url) throws MalformedURLException
        {
            String id = null;
            try
            {
                String query = new URL(url).getQuery();
                if (query != null)
                {
                    String[] param = query.split("&");
                    for (String row : param)
                    {
                        String[] param1 = row.split("=");
                        if (param1[0].equals("v"))
                        {
                            id = param1[1];
                        }
                    }
                }
                else
                {
                    if(url.contains("embed"))
                    {
                        id = url.substring(url.lastIndexOf("/") + 1);
                    }
                }
            }
            catch(Exception ex)
            {
                Log.e("Exception", ex.toString());
            }
            return id;
        }
    

提交回复
热议问题